Divide using partial quotients is closely related to divide using repeated subtraction.
In the lesson about divide using repeated subtraction, we divided 28 by 5 and we came up with the following.
____
5 ) 28
-5 1
________
23
-5 1
_________
18
-5 1
__________
13
-5 1
__________
8
-5 1
__________
3
Notice that 5 is subtracted five times. Subtracting 5 five times is the same as subtracting 25. Therefore, instead of subtracting 5 five times, you can just subtract 25 once.
When you do it like that, you are just subtracting greater multiples of the divisor. Notice that we call 5 partial quotient. Although in this problem, there is only one partial quotient, you will in practice get more than 1 partial quotient as example #2 below shows.
____
5 ) 28 Partial quotients
-25 5 × 5 5
_________
3
Since 3 is less than 5, 3 is the remainder. Thus the answer is 5 r3
Example #2.
Use partial quotients to divide 496 by 4
Step 1
Subtract greater multiples of the divisor. Notice that if we were using repeated subtraction, we would have to subtract 4 one hundred times! Now you see why it is good to divide using partial quotients.
Step 2
Subtract lesser multiples of the divisor.
Step 3
Add the partial quotients. All the steps are shown below.
_______
4 ) 496 Partial quotients
-400 100 × 4 100
________
96
-80 20 × 4 20
________
16
-16 4 × 4 4
________
0
After adding the partial quotients, the answer is 100 + 20 + 4 = 124
496 ÷ 4 = 124
Example #3.
Use partial quotients to divide 786 by 7
_______
7 ) 786 Partial quotients
-700 100 × 7 100
________
86
-70 10 × 7 10
________
16
-14 2 × 7 2
________
2
After adding the partial quotients, we get is 100 + 10 + 2 = 112
We also have a leftover or a remainder of 2.
Therefore, using partial quotients, 786 divided by 7 is 112 r2
The meaning of 112 r2 is a quotient of 112 with a remainder of 2.
Did you find the examples above tough to understand? Did you not understand them at all? Please take a look at this figure!