Factoring algebraic expressions
Factoring algebraic expressions require a solid understanding of how to get the
greatest common factor (GCF)
I will not repeat the whole process here. Therefore, go
here and review how to get the
GCF before you start studying this lesson.
Basically, when factoring algebraic expressions, you will first look for the GCF and use your GCF to make your polynomial look like a multiplication problem:
GCF times( ) or
GCF times( Blank )
where blank is a polynomial with the same amount of term as the original polynomial.
Recall that terms are separated by addition signs, never by multiplication sign.
A few examples about factoring algebraic expressions
Example #1:
Factor x
2y
4 + 2x
2
This expression has two terms. The first term is x
2y
4 and the second is 2x
2
What you see in bold is the GCF:
x2 x2y
4 + 2
x2
So, we are going to make x
2y
4 + 2x
2 look like:
x2 times ( )
Now you need to fill in the blank as shown below:
So, your first term is whatever you multiply
x2 to get x
2y
4.
And whatever you multiply
x2 to get 2x
2 is your second term.
Therefore, x
2y
4 + 2x
2 = x
2(y
4 + 2)
There is an easier way to solve the problem
x2y
4 + 2
x2
Still do
x2 times ( )
Then, in the expression
x2y
4 + 2
x2, take a pencil and cross out or erase the GCF
x2.Then, whatever is left is your first and second term.
Another example
2)
8Y
3B
2 + 16Y
2B
Rewrite the expression as: 8 × Y
2 × Y × B × B + 8 × 2Y
2B
Everything in bold is the GCF
8 ×
Y2 × Y × B ×
B +
8 × 2
Y2B
The GCF is
8Y2B. The answer looks like
8Y2B × ( )
In the expression
8 ×
Y2 × Y × B ×
B +
8 × 2
Y2B, erase the GCF. Whatever is left is your first and second term.
The answer is
8 ×
Y2 × Y × B ×
B +
8 × 2
Y2B =
8Y2B × (YB + 2)
3)
If instead you were factoring 8Y
3B
2 − 16Y
2B, you will do the same thing with the exception
that there will be a minus sign between the two terms. That is all!
8Y
3B
2 − 16Y
2B = 8Y
2B × (YB − 2)
4)
Factor 5(x-2) + 6x(x-2)
Everything in bold is your GCF 5
(x-2) + 6x
(x-2)
So,
(x-2) × ( 5 + 6x)