Pythagorean Theorem

Explore the Pythagorean theorem with the interactive lesson below. See how the area of the red square + the area of the blue square is equal to the area of the gray square. 

Tips: to find the area of a square, just count the number of small squares inside of it. Align to Grid or Rotate the gray square so you can easily count the number of small squares inside of the squares.

Interactive Pythagorean Theorem

Quiz

What is the Pythagorean theorem?

The Pythagorean Theorem was named after famous Greek mathematician Pythagoras. It is an important formula that states the following: a2 + b2 = c2

Pythagorean theorem

Looking at the figure above, did you make the following important observation? This may help us to see why the formula works.

  • The red square has 2 triangles in it 
  • The blue square has also 2 triangles in it
  • The black square has 4 of the same triangle in it
Pythagorean theorem

Therefore, area of red square  + area of blue square = area of black square

Let a = the length of a side of the red square

Let b = the length of a side of the blue square

Let c = the length of a side of the black square

Therefore, a2 + b2 = c2

Generally speaking, in any right triangle, let c be the length of the longest side (called hypotenuse) and let a and b be the length of the other two sides (called legs).

Right triangle
The theorem states that the length of the hypotenuse squared is equal to the length of side a squared plus the length of side b squared. Written as an equation, c2 = a2 + b2

Thus, given two sides, the third side can be found using the formula.

We will illustrate with examples, but before proceeding, you should know how to find the square root of a number and how to solve one-step equations.

Examples showing how to use the Pythagorean theorem


Exercise #1

Let a = 3 and b = 4. Find c, or the longest side

c2 = a2 + b2

c2 = 32 + 42

c2= 9 + 16

c2 = 25

c = √25

The sign (√) means square root

c = 5

Exercise #2

Let c = 10 and a = 8. Find b, or the other leg.

c2 = a2 + b2

102 = 82 + b2

100 = 64 + b2

100 - 64 = 64 - 64 + b2 (minus 64 from both sides to isolate b2 )

36 = 0 + b2

36 = b2

b = √36 = 6

Exercise #3

Let c = 13 and b = 5. Find a

c2 = a 2+ b2

132 = a2 + 52

169 = a2 + 25

169 - 25 = a2 + 25-25

144 = a2 + 0

144 = a2

a = √144 = 12