Simplifying algebraic expressions with one or more variables by combining like terms is what this lesson will show you.
Learning first to simplify numerical expressions will make it easier to understand how to simplify algebraic expressions.
Let's say you want to simplify 5 + 5 + 5 + 5. What is a quick way to get the answer?
You can do 4 × 5 and 4 × 5 is a simplified version of 5 + 5 + 5 + 5.
If you had the following problem to simplify 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5, you can quickly see why it would be useful to just count how many fives there are and then times the amount by 5.
Since there are 11 fives, the simplified expression is 11 × 5
In the same manner, to simplify example #1, just count how many v's there are and multiply the amount by v.
Example #1:
Try to simplify v + v + v + v + v + v
Since there are 6 of them, v + v + v + v + v + v = 6 × v.
To simplify 6 × v even further, you can write 6v. However, remember that there is a multiplication between 6 and v.
Example #2:
Now, try to simplify v + v + v + v + x + x + x
I hope it makes sense to you that you cannot add v and x. What is v + x?
You cannot say 2v because it is v + v that is equal to 2v.
You cannot say 2x because it is x + x that is equal to 2x
Basically v and x are not like terms, so v + x is just equal to v + x.
By the same token, there is another thing you need to watch for. What is v + 2? It is not 2v as already shown.
Again, v and 2 are not like terms either, so v + 2 = v + 2
However, since you can add all the v's, we call the v's like terms. It is the same for the x's. They are called like terms. You can use parenthesis to put together the like terms.
v + v + v + v + x + x + x = (v + v + v + v) + (x + x + x) = 4 × v + 3 × x = 4v + 3x
Example #3:
What about 4v + 3x + 5v + 4x?
You cannot add 4v to 3x, but you can add 4v to 5v. And you can add 3x to 4x
4v + 3x + 5v + 4x = 4v + 5v + 3x + 4x = 9v + 7x
When simplifying algebraic expressions, like terms can have more than one variable.
For example what is xy + xy + xy + xy + xy + xy?
How many xy's do you see? Since there are 6 of them, xy + xy + xy + xy + xy + xy = 6xy
We do have a multiplication between x and y, but it does not change anything.
In the same way, 8xyzf + 12xyzf + xyzf + xyzf + xyzf = 20xyzf + 3xyzf = 23xyzf
v + v + v + v + v + v = 1v + 1v + 1v + 1v + 1v + 1v = (1 + 1 + 1 + 1 + 1 + 1)v = 6v
This shows you a couple of things.
First, notice that putting a 1 next to each v will not change the answer.
1v = v.
Then, when simplifying algebraic expressions, you can just do your math with the number on the left on the variable.
Finally, when simplifying algebraic expressions, subtraction and/or putting negative numbers work pretty much the same way. You can only subtract like terms! The only difficulty you will encounter is the subtraction or addition of integers.
Example #4:
Simplify 4v - 3x - 2v + 4x
I can do 4v with 2v. However, be very careful! The operation on the left of 2v is subtraction, so you have to do 4v - 2v = 2v
In the same way, I can do 3x with 4x, but the operation next to 3x is subtraction. You have to change the subtraction to + -
Then, you will do -3x + 4x = 1x. I hope you have mastered how to add integers
4v - 3x - 2v + 4x = 2v + 1x
You still get the same answer if you change the minus sign(-) into plus negative(+ -)
4v - 3x - 2v + 4x = 4v + -3x + -2v + 4x = 4v + -2v + -3x + 4x = 2v + 1x
Example #7:
6x3 + 4y2 + -2xy + 4y + -4x3 + y2 + 6xy - 9y + x + 6
First, put the like terms together
6x3 + -4x3 + 4y2 + y2 + -2xy + 6xy + 4y - 9y + x + 6
Add the coefficients of the like terms
(6 + -4)x3 + (4 + 1)y2 + (-2 + 6)xy + (4 - 9)y + x + 6
2x3 + 5y2 + 4xy + -5y + x + 6
Example #8:
5(x + 2y + -2) + 4(2x - y + 1)
First, use the distributive property to get rid of the parentheses.
5x + 10y + -10 + 8x - 4y + 4
Combine like terms
5x + 8x + 10y - 4y + -10 + 4
13x + 8y + -6
Example #9:
2 × [(3x ÷ x × 2) - 4 × y] + -5 × 2 + 1
First, simplify -5 × 2 + 1 using the order of operations
2 × [(3x ÷ x × 2) - 4 × y] + -10 + 1
2 × [(3x ÷ x × 2) - 4 × y] + -9
Use the order of operations to simplify the expression inside the brackets
2 × [(3 × 2) - 4 × y] + -9
2 × [6 - 4 × y] + -9
2 × (6 - 4y) + -9
12 - 8y + -9
3 - 8y